Question

Please answer quickly

Answer 1

Answer:

i think zero is the answer

nit sure

Step-by-step explanation:

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Answer 2

Hey Friend..

Here is the Solution..

$\frac{a}{b} +\frac{b}{a}= -1\\\\\frac{a^2+b^2}{ab}= -1\\\\a^2+b^2= -ab\\a^2+b^2 +ab = 0$

Now..

$a^3-b^3 = (a-b)(a^2+b^2+ab)$

Since... a² + b² + ab = 0

Putting it in above equation..

We Get..

$a^3 - b^3 = 0$

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Ans = 0

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