Question

please answer

solve it to fin the value of X ​

Answer 1

$\huge{ \underline{ \mathfrak{ \green{ \: Answer}}}}$

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$\boxed{\red{\bold{Assume:}}}$

$\displaystyle{\frac{x}{x+1}} = a$

$\boxed{\red{\bold{Equation \: becomes:}}}$

$a^2 - 5a + 6 =0$

$a^2 - 3a - 2a + 6 = 0$

$a(a - 3) -2(a-3) = 0$

$\boxed{\red{\bold{By\: grouping \: method:}}}$

$(a-3)(a-2)=0$

$a-3 = 0\; \; or\; \;a-2 = 0$

$a =3 \; \; or \; \;a = 2$

$\boxed{\red{\bold{Putting\: a = \displaystyle{\frac{x}{x+1}} : }}}$

$\displaystyle{\frac{x}{x+1}} = 3 \; \; or\; \; \displaystyle{\frac{x}{x+1}} = 2$

$x = 3(x+1) \; \; or \; \; x = 2(x+1)$

$x = 3x + 3 \; \; or \; \; x = 2x +2$

$x -3x = 3 \; \; or \; \; x - 2x = 2$

$-2x =3 \; \; or \; \; -x = 2$

$x= \displaystyle{\frac{-3}{2}} \; \; or \; \; x = -2$

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Answer 2

hope it helps!

#sumedhian ❤❤