Question

please answer soon.......​

Answer 1

➠ AnSwer :-

We may write, -4a = {-2(a + b)} + {-2(a - b)}

Also,

➝ {-2(a + b)} x {-2(a - b)} = 4(a² - b²).

➝4x² - 4ax + (a² - b²) = 0

➝4x²-2(a+b)x -2(a - b)x+(a² - b²) = 0

➝2x {2x - (a + b)} - (a - b){2x - (a+b)} = 0

➝{2x - (a + b)}×{2x - (a - b)} = 0

➝2x - (a + b) = 0 or 2x - (a - b) = 0

➝X = (a+b)/2 or x = (a-b)/2

Hence, (a+b)/2and(a-b)/2 are the roots of the given equation.

Answer 2

$\huge\underline{\overline{\mid{\bold{\red{ANSWER-}}\mid}}}$

4x^2-4ax+ (a^2-b^2)=0

a=4

b=-4a

c=a^2-b^2

b^2-4ac=(-4a)^2-4*4*(a^2-b^2)

=16a^2-16a^2+16b^2

=16b^2 =4b

= -b+- root b^2-4ac/2a

=+4a+4b/8 =+4a-4b/8

=4(a+b)/8 = 4(a-b)/8

=a+b/2 =a-b/2

Therefore value of x is a+b/2 and a-b/2