Question

please answer step by step​

Answer 1

Answer:

1. Here, LHS is x³-y³ and RHS is (x+y) (x²-xy+y²)

So, we need to solve the RHS first....

ie:-

(x+y) (x²-xy+y²)

Opening the brackets, we get....

x(x²-xy+y²) + y(x²-xy+y²)

So, it becomes,

x³-x²y+xy² + x²y - xy² + y³

Taking common terms at a side, we get

= x³ - x²y + x²y + xy² - xy² + y³

= x³ +0 +0 +y³

= x³ + y³

= LHS

Proved.

2. x³-y³ = (x - y) (x² + xy + y²)

Here, LHS = x³ - y³ and RHS = (x-y) (x²+xy + y²)

Now, solving the RHS, we get,....

(x-y) ( x²+xy+y²)

Solving the brackets,....

x(x²+xy+y²) - y(x²+xy+y²)

x³+x²y + xy² - xy² - x²y - y³

Now, taking the common terms at the same side, we get,....

x³+x²y - x²y + xy²-xy² - y³ =0

x³ +0 + 0 - y³ = 0

Finally, we get :-

x³-y³ ie:- LHS....

Proved....

HOPE IT HELPS....

THANKS....