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Answer:
Answer : The range of frequencies of visible light from 3800-7600A^o3800−7600A
o
will be, 7.89\times 10^{14}s^{-1}\text{ to }3.95\times 10^{14}s^{-1}7.89×10
14
s
−1
to 3.95×10
14
s
−1
Explanation : Given,
Wavelength range of visible light = 3800-7600A^o3800−7600A
o
Formula used :
\nu=\frac{c}{\lambda}ν=
λ
c
where,
\nuν = frequency of light
\lambdaλ = wavelength of light
c = speed of light = 3\times 10^8m/s3×10
8
m/s
Now we have to calculate the frequency of 3800A^o3800A
o
wavelength of light.
\nu=\frac{3\times 10^8m/s}{3800\times 10^{-10}m}=7.89\times 10^{14}s^{-1}ν=
3800×10
−10
m
3×10
8
m/s
=7.89×10
14
s
−1
conversion factor used : 1A^o=10^{-10}m1A
o
=10
−10
m
Now we have to calculate the frequency of 7600A^o7600A
o
wavelength of light.
\nu=\frac{3\times 10^8m/s}{7600\times 10^{-10}m}=3.95\times 10^{14}s^{-1}ν=
7600×10
−10
m
3×10
8
m/s
=3.95×10
14
s
−1
Therefore, the range of frequencies of visible light from 3800-7600A^o3800−7600A
o
will be, 7.89\times 10^{14}s^{-1}\text{ to }3.95\times 10^{14}s^{-1}7.89×10
14
s
−1
to 3.95×10
14
s
−1
Explanation:
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Answer:
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