Question

Please answer the 14th question

Answer 1

$<b>Heya mate. (^_-). Solution below.$
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[] Given,

First side of the triangular park, a = 120 m

Second side of the triangular park, b = 80 m

Third side of the triangular park, c = 50 m



=>>> Then,

Perimeter of the park, P

= a + b + c

= 120 + 80 + 50

= 250 m



=>>> Then,

Semi perimeter of the park, s

= P/2

= 250/2

= 125 m



=>>> Now, by Heron's formula, area of the triangular park,

= √[s (s - a) (s - b) (s - c)]

= √ [125 (125 - 130) (125 - 80) (125 - 50)]

= √[ 125 × 5 × 45 × 75]

= 375√15 m²


•°• Area required to plant grass = 375√15.




[] Now, Perimeter of the park = 250 m



=>>> Then, length of wire needed for fencing,

= 250 m - 3 m... [3 m to be left for a gate]

= 247 m.



=>>> Now, given cost of fencing 1 m = 20 Rs.



=>>> Cost of fencing 247 m

= 20 × 247

= 4940 Rs.

•°• Total cost of fencing = 4940 Rs.
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$<marquee>Thank you and Happy Diwali. (^_-). </marquee>$