Question

please answer the 15th question

Answer 1

Answer:APb=75

Step-by-step explanation:let ABCD be a quadrilateral.angle c+angle d=150.

Angle a+angle b=360 -150=210__-eqn(1).n ow bisectors of a and b meet at P.now in triangle abp angle a +angle b=1/2×eqn (1) =1/2×210=105.so angle APb =180-105=75

Answer 2

Answer:

Angle APB = 75'

Step-by-step explanation:

W.K.T,

In a quadrilateral sum of all angles is 360'.

Given,

Angle D=50'

Angle C=100'

Therefore,

Angle A +Angle B = 360 - Angle D + Angle C.

Ang A + Ang B = 210 °.

Now in triangle APB,

Angle A and Angle B are bisected

A+B+P = 180°.

Therefore

A + B will be 105° in this triangle.

Hence

105°+P = 180

P = 75°

Angle APB is equal to 75° !!!!!!