Question

Please answer the 2nd question​

Answer 1

Answer:0

Step-by-step explanation:

Answer 2

$\dfrac{log_{4}17}{log_{9}23} = \dfrac{log_{2}17}{log_{3}23}$

Write 4 as the square of 2 and 9 as square of 3

☛ $\dfrac{log_{2^2}17}{log_{3^2}23} = \dfrac{log_{2}17}{log_{3}23}$

Using $log_a^{y} (b) = \dfrac{1}{y} \times log_a (b)$ transform the expression

☛ $\dfrac{{\dfrac{1}{2} \times log_{2}(17)}} {\dfrac{1}{2} \times log_{3}(23)} - \dfrac{log_{2}(17)}{log_{3}(23)}$

Reduce the fraction

☛ $\dfrac{log_{2}(17)}{log_{3}(23)} - \dfrac{log_{2}(17)}{log_{3}(23)}$

Eliminate the opposites

☛ 0

∴ The answer is option (A) i.e. 0