Question

Please answer the above math question from class 9 CBSE,Chapter 1

Answer 1

answer



thanks for asking

Answer 2

HELLO DEAR,

$\frac{32}{243}^{\frac{-3}{5}} \\ \\ = \frac{243}{32}^\frac{3}{5} \\ \\= (\frac{3^{5}}{2^{5}})^\frac{3}{5} \\ \\= (3/2)^\frac{5*3}{5} \\ \\= (3/2)^{3} \\ \\ = (27/8) \\ \\ I\:\: HOPE\:\: ITS\:\: HELP \:\:YOU, \\ THANKS$