Question

please answer the above question​

Answer 1

2) -18/5

3) rs.75

4) frequency

hope it helps u.

Answer 2

$\large\sf\underline{Question\:1\::}$

The quantity to be added to $\sf\:\frac{-1}{5}$ to get $\sf\:\frac{17}{5}$ is

a) $\sf\:\frac{-5}{18}$

b) $\sf\:\frac{-18}{5}$

c) $\sf\:\frac{12}{5}$

d) $\bf\:\frac{18}{5}$ ☑

‎

$\large\sf\underline{Solution\::}$

Let x be added to $\sf\:\frac{-1}{5}$ to get $\sf\:\frac{17}{5}$ .

Now framing up a equation :

$\sf\implies\:\frac{-1}{5} + x = \frac{17}{5}$

• LCM of 5 and 1 = 5

$\sf\implies\:\frac{-1+5x}{5} = \frac{17}{5}$

• Cross multiplying

$\sf\implies\:5(-1+5x)= 17 \times 5$

$\sf\implies\:-5+25x= 85$

• Transposing -5 to other side it becomes +5

$\sf\implies\:25x= 85+5$

$\sf\implies\:25x= 90$

• Transposing 25 to other side it goes to the denominator

$\sf\implies\:x= \frac{90}{25}$

• Reducing it to lower terms

$\sf\implies\:x= \cancel{\frac{90}{25}}$

$\small{\underline{\boxed{\mathrm\red{\implies\:x\:=\:\frac{18}{5}}}}}$ ★

‎

$\large\sf\underline{Verifying\::}$

$\sf\implies\:\frac{-1}{5} + x = \frac{17}{5}$

• Substituiting the value of x we got

$\sf\implies\:\frac{-1}{5} +\frac{18}{5} = \frac{17}{5}$

• LCM of 5 and 5 = 5

$\sf\implies\:\frac{-1+18}{5}= \frac{17}{5}$

$\sf\implies\:\frac{17}{5}= \frac{17}{5}$

$\large{\mathfrak\blue{hence\:verified\:!¡}}$

‎ ____________________________

$\large\sf\underline{Question\:2\::}$

The SI on Rs 250 at 10 % p.a for 3 years is

a) Rs 25

b) Rs 75 ☑

c) Rs 40

d) Rs 45

‎

$\large\sf\underline{Solution\::}$

Formula for SI = $\sf\:\frac{P \times R \times T}{100}$

where :

• SI = Simple Interest

• P = Principal

• R = Rate

• T = Time

Substituiting the given values in the formula :

$\sf\to\:SI\:=\frac{250 \times 10 \times 3}{100}$

$\sf\to\:SI\:=\frac{2500 \times 3}{100}$

$\sf\to\:SI\:=\frac{7500}{100}$

$\sf\to\:SI\:=\cancel{\frac{7500}{100}}$

$\small{\underline{\boxed{\mathrm\red{\to\:SI\:=\:Rs\:75}}}}$ ★

____________________________‎

$\large\sf\underline{Question\:3\::}$

The number of times an observation occurs in a data is called :

a) range

b) frequency ☑

c) class size

d) none of these

‎

$\large\sf\underline{Solution\::}$

$\small{\underline{\boxed{\mathrm\red{Frequency}}}}$ ★

$\dag\:\underline{\sf More \:to\:know\::}$

$\tt\orange{Range}$ = The difference between the maximum and minimum values is called the range.

$\tt\orange{Frequency}$ = The number of times an observation occurs in a data is called frequency.

$\tt\orange{Class\:size}$ = The difference between the upper limit and lower limit of a class interval is called the range.

____________________________

‎

!! Hope it helps !!