Question

Please answer the above question as soon as possible.​

Answer 1

DATA- ABCD is a parallelogram

            AC and BD are diagonals intersecting at M

TO PROVE-  M is mid point of LN

PROOF- In  ΔAML and ΔCMN

               ∠MAL = ∠MCN(alternate interior angles)

               ∠AML = ∠CMN(vertically opposite angles)

               AM = CM (diagonals in a parallelogram bisect each other)

           ∴ ΔAML ≈ ΔCMN

        ∴LM = NM (cpct)

    ∴M is the  midpoint of LN