please answer the above question fast 2,3,5,6
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mudrabhandari1p4cb5t:
2-2. 3-4. 6-1
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3)
Cvmixture = n1 Cv1 + n2 Cv2/ n1 +n2
Cvmix =( 2 5R/2 + 4 3R/2 )/2+4
Cvmix = 11R/6
ΔU=n cvmix T
ΔU= 6 x 11Rt/6 T
ΔU =11RT
5)
ΔU1 =ΔU2
n1cv1ΔT1 = n2cv2ΔT2
0.5x 5R/2. (t-27)= 0.5 x 5R/2 x 47-t
2t =74
t=37 °C
Cvmixture = n1 Cv1 + n2 Cv2/ n1 +n2
Cvmix =( 2 5R/2 + 4 3R/2 )/2+4
Cvmix = 11R/6
ΔU=n cvmix T
ΔU= 6 x 11Rt/6 T
ΔU =11RT
5)
ΔU1 =ΔU2
n1cv1ΔT1 = n2cv2ΔT2
0.5x 5R/2. (t-27)= 0.5 x 5R/2 x 47-t
2t =74
t=37 °C
why not t-47 in question 5
Amey
U r there
becoz temp is decreasing from 47 to t and in lhs temp. increases from 27 to t and ΔT cannot be negetive thats y itx 47-t not t -47
thanx
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