Please answer the above question in the pic
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→Frictional force per metric ton is 10N
→Frictional force on train =10×600=6000N
→Froctional force on Loco =10×150=1500N
→Net F =6000+1500=7500N
Power P=FV
=7500×15=112.5Kw
options c is correct✅✅
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[tex] \huge \text {AnSwEr}
→Frictional force per metric ton is 10N
→Frictional force on train =10×600=6000N
→Froctional force on Loco =10×150=1500N
→Net F =6000+1500=7500N
Power P=FV
=7500×15=112.5Kw
options c is correct✅✅
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