Physics, asked by mahirdesai23, 9 months ago

Please answer the above question in the pic​

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Answered by Anonymous
7

\underline\bold\red{AnswEr}

→Frictional force per metric ton is 10N

→Frictional force on train =10×600=6000N

→Froctional force on Loco =10×150=1500N

→Net F =6000+1500=7500N

Power P=FV

=7500×15=112.5Kw

options c is correct✅✅

Answered by Anonymous
2

[tex] \huge \text {AnSwEr}

→Frictional force per metric ton is 10N

→Frictional force on train =10×600=6000N

→Froctional force on Loco =10×150=1500N

→Net F =6000+1500=7500N

Power P=FV

=7500×15=112.5Kw

options c is correct✅✅

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