Math, asked by likitha20052, 2 months ago

please answer the as soon as possible.​

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Answered by shrabantijana5811
1

Answer:

f is a function.

f(x) =3x-3 when x>3

=x^2 -2 , when -2<=x<=2

=2x+1 , when x<-3

⚫f(4)

here 4 >3 so, f(4) = 3*4-2=12-2=10

f(4)=10

⚫f(2.5) doesn't exist.

⚫f(-2)=(-2)^2-2=4-2=2.[ since, (-2) belongs to{ x^2 -2 , when -2<=x<=2}]

⚫f(-4) =2*(-4) +1=(-8+1)=-7.[ since, (-2) belongs to {2x+1 , when x<-3} and -4<-3]

⚫f(0) =0^2-2=2, [since, 0 belongs to {x^2 -2 , when -2<=x<=2}]

⚫f(-7)=2*(-7)+1=-14+1=-13

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