please answer the as soon as possible.
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f is a function.
f(x) =3x-3 when x>3
=x^2 -2 , when -2<=x<=2
=2x+1 , when x<-3
⚫f(4)
here 4 >3 so, f(4) = 3*4-2=12-2=10
f(4)=10
⚫f(2.5) doesn't exist.
⚫f(-2)=(-2)^2-2=4-2=2.[ since, (-2) belongs to{ x^2 -2 , when -2<=x<=2}]
⚫f(-4) =2*(-4) +1=(-8+1)=-7.[ since, (-2) belongs to {2x+1 , when x<-3} and -4<-3]
⚫f(0) =0^2-2=2, [since, 0 belongs to {x^2 -2 , when -2<=x<=2}]
⚫f(-7)=2*(-7)+1=-14+1=-13
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