Math, asked by 1100070, 8 months ago

please answer the below question

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Answered by Anonymous
2

Two dice are thrown simultaneously

S={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

n(S)=36

Condition A : The sum of the number on two dice is >10

A ={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),

(5,1),(5,2),(5,3),(5,4),

(6,1),(6,2),(6,3)}

n(A) = 30

P(A)=n(A)

=30/36

=5/6

Condition B: A doublet

B={(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}

n(B)=6

P(B)= n(B)/n(S)

=6/36

=1/6

I hope this will help you.....

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