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#4
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Divyankasc:
Ting tong! Doubt! How is sin²A.cos²A = sin²A/2 / 4 in 5th and 6th step
sin2A = 2sinAcosA, so squaring both sides and here A = A/2......sorry there is a mistake...that should not be A/2...that should be 2A, but sin2A also have the same maximum and minimum value
no no....dont put A= A/2.....just correct stated mistake...rest is correct
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Is something wrong in the answer ?
yes....actually sin2A= 2sinAcosA...ok,,,,means (sin2A)/2 = sinAcosA...now squaring both sides....i should have write sin²2A instead of sin²A/2
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