Math, asked by Faiqa93, 1 year ago

Please answer the following question in the image.
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Answers

Answered by Anonymous
2
Hii dear

ur answer




Answer:


Step-by-step explanation:

3x + y =1


(2k-1)x+(k-1)y=2k+1


=> 3x+y-1=0


(2k-1)x+(k-1)y-2k-1 =0


We know,


a1/a2 = b1/b2 not equal to c1/c2 has no solution



Now,we have,


a1=3 , b1=1


a2=2k-1 , b2 = k-1


3/2k-1 = 1/k-1


3(k-1) = 2k -1


3k-3 = 2k -1


3k -2k = -1 +3


k = 2



I hope it will help you



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