Math, asked by IndraHero04, 10 months ago

please answer the following question today is my exam​

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Answers

Answered by Anonymous
18

SOLUTION

Refer to the attachment.

hope it helps ☺️

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Answered by Anonymous
7

Hii

you are welcome in my ans

RHS

1 - tan@/1 -l+ tan@

cos@ - sin@/ cos@ + sin@

(cos^2@ - sin^2@)/ (cos@ +sin@)^2

cos2@ / 1+ sin2@

LHS

from LHS

cos2@ /1+ sin2@

cos^2@ - sin^2@/ (cos@ + son@)^2

(cos@ + sin@)(cos@ - sin@)/(cos@ +sim@)^2

cos@ - sin@ /cos@ + sin@

sqrt2(cos@ sinπ/4 - cosπ/4sin@)/sqrt2(cos@cosπ/4 + sinπ/4 sin@)

sin(π/4 - @)/cos(π/4 - @)

tan(π/4 - @)

RHS

_/\_☺️

Hope it may helps you

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