please answer the following questions
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sin3theta +cos3theta is a3+b3=(a+b)(a2-ab+b2)
(sin+cos)(sin2-sincos+cos2)/(sin+cos) + sincos
the numerator and denominator's (sin+cos) gets cancel
left:(sin2-sincos+cos2+sincos) after cancelation
we get (sin2 +cos2) =1
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