Please answer the given question in the picture ?
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AC^2=AB^2+BC^2
AC^2=(1)^2+(√3)^2
AC^2=1+3
AC^2=4
AC=√4
AC=2
sin(90-theta)=cos theta
cos theta=BC/AC
cos theta=√3/4
Hope, this helps you.
AC^2=(1)^2+(√3)^2
AC^2=1+3
AC^2=4
AC=√4
AC=2
sin(90-theta)=cos theta
cos theta=BC/AC
cos theta=√3/4
Hope, this helps you.
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