Math, asked by SS07, 9 months ago

Please answer the given Questions

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Answered by dsudha880
0

Answer:

11.a)

(2a-3b-c)

here,

a=2a

b=3b

c=c

it is in the form of (a-b-c)^2

(a-b-c)^2=a^2+b^2+c^2-2ab+2bc-2ca

=>(2a)^2+(3b)^2+(c)^2-2(2a×3b)+2(3b×c)-2(c×2a)

=>4a^2+9b^2+c^2-8ab+6bc-4ca

hope it may help you

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