☺ Please answer the picture.
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Q - 7 & 8.
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sin A = P/H = 11/61
We can take P = 11 and H = 61 for simplicity
>> B^2 = H^2 - P^2 = 3721 -121 =3600
>> B = 60
cos A = B/H = 60/61
tan A = P/B = 11/60
sec A = H/B = 61/60
Similarly for next question
cos A = B/H =4/5
B = 4, H = 5
P = 3 by pythgoras
sin A = P/H = 3/5
cot A = B/P = 4/3
We can take P = 11 and H = 61 for simplicity
>> B^2 = H^2 - P^2 = 3721 -121 =3600
>> B = 60
cos A = B/H = 60/61
tan A = P/B = 11/60
sec A = H/B = 61/60
Similarly for next question
cos A = B/H =4/5
B = 4, H = 5
P = 3 by pythgoras
sin A = P/H = 3/5
cot A = B/P = 4/3
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