Question

please answer the question

Answer 1

Answer:

in triangle ADE and triangle ABC

we have:

AB=AD(given)

AC=AE(given)

and angle BAD=angleEAC=angleCAE

let angleDAC=X

then angle BAC=angleBAD+X

and angle DAE=angleCAE+X

and hence,

angle BAD= angle CAE

and angle DAC=X

we have angleBAC=angleDAE

so,triangle BAC or ABC is congruent

to triangle DAEor ADE

and hence,BC=DE(by C.P.C.T.)

Answer 2

Step-by-step explanation:

Angle BAD = Angle EAC

Add angle CAD on both sides

Angle BAD +CAD =Angle EAC +CAD

Angle BAC = Angle EAC

In triangles AED and ABC

AC =AE - given

AB=AD - given

Angle BAC =Angle EAC -proved above

Hence

Triangle AED is congruent to ABC

By CPCT

BC =DE