Question

Please answer the question.

Answer 1

Answer:

coordinate of,

A(3,k)

B(0,2)

C(k,5)

since B is equidistant from A and C

distance of AB=distance of BC

√(x2-x1)²+(y2-y1)²=√(x3-x2)²+(y3-y2)²

squaring both sides,

[√(0-3)²+(2-k)²]²=[√(k-0)²+(5-2)²]²

(-3)²+(2-k)²=(k)²+(3)²

9+4+k²-4k=k²+9

k²-k²-4k=9-9-4

-4k=-4

K=1