please answer the question 19 its urgent...
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It means we have to find the number which lies between them
so for that we should do
1/2(11/3+3/11)
1/2(121/33+9/33)
1/2(130/33)
ans=65/33
so for that we should do
1/2(11/3+3/11)
1/2(121/33+9/33)
1/2(130/33)
ans=65/33
anshi6:
thanks
i am expert in mathematics.i got first rank in bihar in sirverzone olympiad
wow
can you believe it?
why not
can i ask you few more questions
sonu plz tell me the in ellipse Ab=2a,CD=2b and f1f2=2c then prove (a^2-c^2)=b^2
hey anshi u can ask question i 'll help u...
if i can...
ask ...
Answered by
1
(3/11 +11/3)÷2
=(9/33+121/33)÷2
=(130/33)÷2
=130/66
=65/33
in this type of questions you have to find out average of two numbers
I hope this solution would help you
=(9/33+121/33)÷2
=(130/33)÷2
=130/66
=65/33
in this type of questions you have to find out average of two numbers
I hope this solution would help you
thank you
can you please write the whole process
can i ask you few more questions??
i don't have time at the moment.can you please ask question tomorrow
because i have a lot homework today
mee too
ok bye
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