Question

please answer the question​

Answer 1

Answer :-

In the ∆BDC , A is the midpoint of the side BD Ratio of length, BA : AD = Ratio of Area's of Traingles , BAC : ADC = 1 : 1

$\therefore \: \: \: \: \:$

Area of ∆ BAC = 1/2 OF ∆BDC

Area of ∆ ADC = 1/2 OF ∆ BDC

Then, E is the midpoint of the line AC .

Therefore , Area of ∆BAE=1/2 OF 1/2 BDC

= 1/4 OF ∆BDC

Similarly,,, Area of ∆ADE = 1/2 OF 1/2 ∆BDC

=1/4 OF ∆BDC

Area of ∆CDE = 1/2 OF 1/2 ∆BDC

= 1/4 OF ∆BDC

Area of ∆CBE = 1/2 OF 1/2 ∆BDC

= 1/2 OF ∆BDC

Hope it helps to you...