please answer the question
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I can't see it properly
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a quadrilateral=360° so
<A+<B+<C+<D=360°
let us keep the angles as x
85°+76°+x+x=360°
161°+2x=360°
2x=360°-161°
2x=199
x=199/2
x=99.5°
so 99.5°+99.5°+76°+85°=360°= a quadrilateral
hope this helps u dude
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