Question

please answer the question.​

Answer 1

Answer:

please mark me as brainliast...

Answer 2

Answer:

I have done the question by 3 ways, you can do any one of them.

Step-by-step explanation:

in ∆ABD and ∆CDB

BD=BD (common)

angle ADB = angle CDB. (90°each)

AD=CD. ( BD is the bisector)

by SAS congurency

∆ABD =~ ∆CDB

OR

in ∆ABD and ∆CDB

angle ADB = angle CDB. (90°each)

AB = CB ( ∆ABC is an equilateral triangle)

AD= CD ( BD is the bisector)

by RHS congurency

∆ABD =~ ∆CDB

OR

in ∆ABD and ∆CDB

AB = CB ( ∆ABC is an equilateral triangle)

AD= CD ( BD is the bisector)

AD = AD (common)

by SSS congurency

∆ABD =~ ∆CDB