Question

please answer the question..​

Answer 1

✯ Topic ☛ Data Handling .

✯ Your Question ☟

• ➥ In the given attachment by you.

✯ Formula Used ☛ Using empirical formula. $\\ ✯\underline[{\boxed{\tt Mode=3(Median)-2(Mean)}}]✯$

✯ Explanation ☟

✠ See the attachment first.

$✰ \: \tt \: \underline {Mean} \: : \implies \: \frac{ \sum \boldsymbol{f}_{ \it i} \boldsymbol{x}_{ \it i}}{ \sum\boldsymbol{f}_{ \it i}} : \implies \: \frac{258}{50}: \implies \underline{\:5.16}$

$❍  \underline{ \tt \: We \: have, \: \bf N : \implies \: 50, \: \tt which \: is \: even.}$

$\therefore \: \tt Median \: : \implies \: \frac{1}{2} \bigg \lbrace \big\lgroup \frac{N}{2} \big\rgroup{}^{th} \: item \: + \big\lgroup \frac{N}{2} + 1 \big\rgroup{}^{th} \: \: item\bigg \rbrace \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: : \implies \tt\frac{1}{2} \bigg \lbrace \big\lgroup \frac{50}{2} \big\rgroup{}^{th} \: item \: + \big\lgroup \frac{50}{2} + 1 \big\rgroup{}^{th} \: \: item\bigg \rbrace \\ \\ \tt : \implies \: \frac{1}{2} \lbrace 25 {}^{th} \: item \: + \: 26 {}^{th} \: item \rbrace \\ \\ \tt: \implies \frac{1}{2} (5 + 5) \implies \frac{10}{2} \bf\implies \: 5.$

$❒ \: \: \underline{\tt \: Now, \: Mode \: : \implies \: \bf 3(Median) - 2(Mean)} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt: \implies \: 3 \times \bf 5 \tt - 2 \times \bf 5.16 \implies \tt 15 - 10.32 \implies \: \bf 4.68.$

$\: \underline{\boldsymbol{\therefore \: Hence}, \tt\: Mean \: \: \bf: \implies 5.16, \tt \:Median \: \: : \implies \bf5, \tt \: \: Mode \: \: : \implies \bf \: 4.68.}$

✯ Another Question Related to it ☟

https://brainly.in/question/15851315?utm_source=android&utm_medium=share&utm_campaign=question

✯ Hope it helps u ✯

Answer 2

Answer:

✯ Topic ☛ Data Handling .

\begin{gathered}\\\\\end{gathered}

✯ Your Question ☟

\begin{gathered}\\\end{gathered}

➥ In the given attachment by you.

\begin{gathered}\\\\\end{gathered}

✯ Formula Used ☛ Using empirical formula. \begin{gathered}\\ ✯\underline[{\boxed{\tt Mode=3(Median)-2(Mean)}}]✯\end{gathered}

✯

[

Mode=3(Median)−2(Mean)

]✯

\begin{gathered}\\\\\end{gathered}

✯ Explanation ☟

\begin{gathered}\\\\\end{gathered}

✠ See the attachment first.

\begin{gathered}\\\\\end{gathered}

\begin{gathered}✰ \: \tt \: \underline {Mean} \: : \implies \: \frac{ \sum \boldsymbol{f}_{ \it i} \boldsymbol{x}_{ \it i}}{ \sum\boldsymbol{f}_{ \it i}} : \implies \: \frac{258}{50}: \implies \underline{\:5.16} \\ \\ \end{gathered}

✰

Mean

:⟹

∑f

i

∑f

i

x

i

:⟹

50

258

:⟹

5.16

\begin{gathered}❍ \underline{ \tt \: We \: have, \: \bf N : \implies \: 50, \: \tt which \: is \: even.} \\ \\ \end{gathered}

❍

Wehave,N:⟹50,whichiseven.

\begin{gathered}\therefore \: \tt Median \: : \implies \: \frac{1}{2} \bigg \lbrace \big\lgroup \frac{N}{2} \big\rgroup{}^{th} \: item \: + \big\lgroup \frac{N}{2} + 1 \big\rgroup{}^{th} \: \: item\bigg \rbrace \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: : \implies \tt\frac{1}{2} \bigg \lbrace \big\lgroup \frac{50}{2} \big\rgroup{}^{th} \: item \: + \big\lgroup \frac{50}{2} + 1 \big\rgroup{}^{th} \: \: item\bigg \rbrace \\ \\ \tt : \implies \: \frac{1}{2} \lbrace 25 {}^{th} \: item \: + \: 26 {}^{th} \: item \rbrace \\ \\ \tt: \implies \frac{1}{2} (5 + 5) \implies \frac{10}{2} \bf\implies \: 5. \\ \\ \end{gathered}

∴Median:⟹

2

1

{

⎩

⎪

⎧

2

N

⎭

⎪

⎫

th

item+

⎩

⎪

⎧

2

N

+1

⎭

⎪

⎫

th

item}

:⟹

2

1

{

⎩

⎪

⎧

2

50

⎭

⎪

⎫

th

item+

⎩

⎪

⎧

2

50

+1

⎭

⎪

⎫

th

item}

:⟹

2

1

{25

th

item+26

th

item}

:⟹

2

1

(5+5)⟹

2

10

⟹5.

\begin{gathered} ❒ \: \: \underline{\tt \: Now, \: Mode \: : \implies \: \bf 3(Median) - 2(Mean)} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt: \implies \: 3 \times \bf 5 \tt - 2 \times \bf 5.16 \implies \tt 15 - 10.32 \implies \: \bf 4.68. \\ \\ \end{gathered}

❒

Now,Mode:⟹3(Median)−2(Mean)

:⟹3×5−2×5.16⟹15−10.32⟹4.68.

\begin{gathered} \: \underline{\boldsymbol{\therefore \: Hence}, \tt\: Mean \: \: \bf: \implies 5.16, \tt \:Median \: \: : \implies \bf5, \tt \: \: Mode \: \: : \implies \bf \: 4.68.} \\ \\ \\ \end{gathered}

∴Hence,Mean:⟹5.16,Median:⟹5,Mode:⟹4.68.

✯ Another Question Related to it ☟

https://brainly.in/question/15851315?utm_source=android&utm_medium=share&utm_campaign=question

\begin{gathered}\\\\\end{gathered}

✯ Hope it helps u ✯