Question

Consider the following frequency distribution:

Class

0-5

6-11

12-17

18-23

24-29

Frequency

13

10

15

8

11

Find the upper limit of the median class.
please answer it is important for my pre board exam​

Answer 1

Answer:

hiiii

Step-by-step explanation:

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hope so u are fine

Answer 2

Answer:

Answer

Classes are not continuous, hence make them continuous by adding 0.5 to the upper limits and subtracting 0.5 from the lower limits.

C.I Frequency Cumulative Frequency

0−5.5 13 13

5.5−11.5 10 23

11.5−17.5 15 38

17.5−23.5 08 46

23.5−29.5 11 57

Total ∑f=57

Class interval can't be negative hence the first C.I. is starting from 0.

Now to find median we calculate

2

∑f

=

2

57

=28.5

∴ Median class 11.5−17.5