please answer the question
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jpatar16:
yes
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Hii.....
sin(A+B) = sinA. cosB + cosA. sinB
cos(A-B) = cosA . cos B + sinA . sinB
{cos(90-a)=sina}
{sin(90-a)=cosa}
cos(90-A-B)=cos(90-A).cos B + sin(90-A).sinB
cos(90-(A+B)= sinA.cosB + cosA.sinB
sin(A+B)=sinA . cosB + cosA . sinB.
sin(A+B) = sinA. cosB + cosA. sinB
cos(A-B) = cosA . cos B + sinA . sinB
{cos(90-a)=sina}
{sin(90-a)=cosa}
cos(90-A-B)=cos(90-A).cos B + sin(90-A).sinB
cos(90-(A+B)= sinA.cosB + cosA.sinB
sin(A+B)=sinA . cosB + cosA . sinB.
no
where do u live
assam
ok
for this prove i don't get 4 or 5 marks
this question is 6 marks question
why i don't get 4 or 5 marks
solved by geometry
ok
ur name
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