please answer the question
A driver of a car travelling at 52 km h applies the brakes and
accelerates uniformly in the opposite direction. The car stops
in 5 s. Another driver going at 3 km h in another car applies
his brakes slowly and stops in 10 s. On the same graph paper,
plot the speed versus time graphs for the two cars. Which of
the two cars travelled farther after the brakes were applied?
please give right answer
Answers
Initial speed of the car A u=52 kmh
−1
=52×
18
5
=14.44 ms
−1
The car stops in 5 seconds i.e v=0 at t=5
(A) : Initial speed of the car A u=3 kmh
−1
=3×
18
5
=0.83 ms
−1
The car stops in 10 seconds i.e v=0 at t=10
With the help of these initial and final points for both the cases, we can plot the graph of speed vs time.
Area under the speed-time graph gives the distance covered.
∴ Distance covered by car A x
A
=
2
1
×14.44×5=36.1 m
∴ Distance covered by car A x
B
=
2
1
×0.83×10=4.15 m
Thus car A travels more distance than B.
solution
Answer:The speed v/s time graphs for the two cars can be plotted as follows.The total displacement of each car can be obtained by calculating the area
beneath the speed-time graph. Therefore, displacement of the first car = area of triangle AOB
= (1/2)*(OB)*(OA)
But OB = 5 seconds and OA = 52 km.h-1 = 14.44 m/s
Therefore, the area of the triangle AOB is given by:
(1/2)*(5s)*(14.44ms-1) = 36 meters
Now, the displacement of the second car is given by the area of the triangle COD= (1/2)*(OD)*(OC)
But OC = 10 seconds and OC = 3km.h-1 = 0.83 m/s
Therefore, area of triangle COD = (1/2)*(10s)*(0.83ms-1) = 4.15 meters
Therefore, the first car is displaced by 36 meters whereas the second car
is displaced by 4.15 meters. Therefore, the first car (which was traveling
at 52 kmph) traveled farther post the application of brakes.
Read more on Brainly.in - https://brainly.in/question/9720001#readmore
Explanation: