Question

Please answer the question attached, it's urgent. ​

Answer 1

Answer:

sin²x + cos²x = 1

cosec (90-x) = secx

and sec (90-x) = cosec x

and tan(90-x)= cot x

hence,

(tan25°÷cosec65°)^2 +(cot25°÷sec65°)^2 +2 (tan18°×tan45°×tan72°)