Question

PLEASE ANSWER THE QUESTION GIVEN BELOW
TOMORROW I HAVE SAHODAYA PRE BOARD MATHS EXAM​

Answer 1

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By taking the L.C.M. and all that stuff we get

$3 {x}^{2} - 6x + 2$

Now taking

$- b + - ( {b}^{2} - 4ac) \div 2a$

We get,

$- 6( + - )2 \sqrt{3} \div 6$

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Answer 2

Refer the attachment give above!

THANKS!