Question

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Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

GIVEN:-

ABCD is a parallelogram, E perp DC , CF perp AD if AB = 18 cm and AE = 6 cm , and CF = 12 cm Find the Area of parallelogram ABCD

To find:-

Area of parallelogram ABCD

SOLUTION:-

As we know,

Area of parallelogram=Base×Height

(Altitudes are also called as Height)

As in the question there are two altitudes

CF and AE

Altitudes will always in figure 90°

(As there are two altitudes we need to two areas but need not add)

I) Base of parallelogram=AB(18cm)

Height of parallelogram=AE(6cm)

By using the formula we get,

=18cm×6cm

$= 108 {cm}^{2}$

ii) Base of parallelogram=AB(18cm)

Height of parallelogram=CF(12cm)

By using the formula we get,

=18cm×12cm

$= 216 {cm}^{2}$

Therefore area of parallelogram ABCD are :-

$108 {cm}^{2} \: and \:216 {cm}^{2}$

Additional Information:-

Area of triangle=

$\frac{1}{2} \times base \times height$

Area of rectangle=Length×Breadth

Area of square=Side×Side

Area of parallelogram=Base×Height

Area of Circle=πr^2

Area of semicircle=

$\frac{\pi \: {r}^{2} }{2}$

Area of Trapezium=

$\frac{a(base) + b(base)}{2} \times height$

Step-by-step explanation:

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