Please answer the question in attachment with proper explanation.
Attachments:
Answers
Answered by
11
hey user
here is your answer
Torque from the centre of Rotation we get,
T = I*a
a is angular accln.
F*R = ((2/5)MR^2 + MR^2)a
we get a = 5F/7MR rad/sec.
Now accln. = a/R
Hence Acom = 5F/7M
where F is the tangential constant Force And M is th mass of the sphere.
I hope you got it
here is your answer
Torque from the centre of Rotation we get,
T = I*a
a is angular accln.
F*R = ((2/5)MR^2 + MR^2)a
we get a = 5F/7MR rad/sec.
Now accln. = a/R
Hence Acom = 5F/7M
where F is the tangential constant Force And M is th mass of the sphere.
I hope you got it
TPS:
Sorry, i didn't get it.
Can you edit your answer and solve it to find acceleration of the shell?
thank you! Edit option will be available for a short time only.
Can you tell me how you got acceleration of COM from the equation? you wrote the equation at the point of contact, not COM, right?
Answered by
4
Pls mark as brainliest
Attachments:
torque eqn from COM
Good answer!
Similar questions