Question

Please answer the question in notebook.

Answer 1

Answer:

for equal roots

b2 - 4ac =0

Step-by-step explanation:

(k+1)² - 4(k+4)1

k²+2k+1 - 4k -16 =0

k² - 2k -15 =0

k² - 5k +3k -15 =0

k (k-5) +3 ( k-5) =0

k = 5 , - 3

so for these values the quad. eqń will have equal roots.