Question

please answer the question mentioned above ​

Answer 1

Answer:

answer for you by sherin

Answer 2

Answer:

(A)Consider parallel plate capacitor is place in vacuum and permittivity of vacuum is given by ϵo

Then,

Electric fields between the plates of capacitor is given by,

E= ϵ o /σ = Aϵ o /Q

potential difference between the plates is given by,

V=Ed= Qd/Aϵ o

But,

Capacitance = C= Q/V

= ϵ o A/d

If we place dielectric medium in between the plates of capacitor then permittivity of medium increases and

it is denoted by ϵ m

Then new capacitance will be,

Capacitance = C= Q/V

= ϵ mA/d

(B)When a metallic plate of thickness t is inserted,

then electric field inside the plate will be zero-

=> E = E₀/k = 0

=> k = ∞

hence putting the value of k in the above equation we get,

C = ε₀A/(d - t)

which is the required expression for capacitance with metallic plate.

Hope it helps!