please answer the question no.8.
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answe1)-we will calculate the distance represented by 1 square of the graph.
5 square on x-axis=2s
1 square on x-axis=2/5s
3 square on x-axis=2m/s
1 square on x-axis=2/3 m/s
so,area of 1 square on graph =2/5×2/3=4/15
1 square represents distance =4/15m
so,62 square representely square come under the area slop for the time of 4s
so,62 is square representely =4/15×65=16.5
answer2)-After 6 sec
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