Question

please answer the question on attachment​

Answer 1

Explanation:

${ {3}^{2} }^{3}  \times  {(2 \times  {3}^{5}) }^{ - 2}  \times  {18}^{2 }  \\  \\  =  {3}^{6}  \times  \frac{1}{4 \times  {3}^{10} }  \times  {18}^{2}  \\  \\  =  \frac{ {18}^{2} }{4 \times  {3}^{4} }  \\  \\  =  \frac{ \cancel{18 } \: ^{ \cancel{6}} \: ^{ \cancel{2}}\times { \cancel{18}}  \: ^{ \cancel{6 }} \:  ^{ \cancel{2}} \:  ^1 }{ { \cancel{4 }\:_1}\times { \cancel{3} \: _1} \times { \cancel{3 } \: _1}\times { \cancel{3} \:_1} \times { \cancel{3} \: _1} }  \\  \\  = { \huge{ \red{ \boxed{1}}}}$

Answer 2

Given :

$\begin{gathered} { \textsf { \textbf{Here}}} \begin{cases} \sf{p(principal) = 40000} \\ \sf{r\%(rate\%) = 10\%(compounded \: half \: yearly)} \\ \sf{n(time) = 4years(compounded \: half-yearly} \\ \end{cases} \end{gathered}$

To find :

• What amount is to be repaid on a loan.

Solution :

As we know the principal , rate and time already given.

Applying the formula for finding the amount.

${ \underline{ \boxed{ \sf{amount = \bigg(1 + \frac{r}{100} \bigg) ^n}}}}$

Substituting the values in the formula , we get :

$\sf \longrightarrow Amount = 40000\bigg(1 + \frac{10}{100} \bigg)^{4}$

$\sf \longrightarrow Amount = 40000 \bigg( \frac{110}{100} \bigg)^{4}$

$\sf \longrightarrow Amount = 40000 \times \frac{110}{100} \times \frac{110}{100} \times \frac{110}{100} \times \frac{110}{100}$

$\sf \longrightarrow Amount = 40,000 \times 1.1 \times 1.1 \times 1.1 \times 1.1$

$\sf \longrightarrow Amount = 40,000 \times (1.1)^4$

$\sf \longrightarrow Amount = 40,000 \times 1.4641$

⠀⠀$\underline{\bf{Amount = 58,564}}$ ⠀

• Hence, ₹58,564 is the required amount which is to be paid.