Math, asked by gajjelarajeswari32, 4 months ago

please answer the question
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Answered by RudranshuMishra7
3

 {( \sqrt{3} )}^{5}  \times  {9}^{2}  =  {3}^{ \alpha }  \times 3 \sqrt{3}  \\  \\  {3}^{3}  \times  { {3}^{2 \times 2} } =  {3}^{ \alpha }  \times 3 \times  {3}^{ \frac{1}{2} }

⇒Base is same. Power will add.

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 {3}^{3 + 4}  =  {3}^{ \alpha }  \times  {3}^{ \frac{3}{2} }  \\  \\  {3}^{7}  =  {3}^{ \frac{3}{2}  +  \alpha }

⇒Now we can equate the powers.

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7 =  \frac{3}{2}  +  \alpha  \\  \\ 7 -  \frac{3}{2}  =  \alpha  \\  \\

 \boxed{ \frac{11}{2}  =   \alpha  = 5.5}

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I hope it helped you ✌.

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manchalanageshreddy: hi rajeswari
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