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Answer 1

Answer:

1. -48

2. 65 is range

3. x+5 = (-12)

=> x= -12-5

=> x= -17

4.A scalene triangles has all sides are unequal.

5.Sum of angles of a triangle = 180⁰

Let the other angle be x

Then , 48⁰+42⁰+x = 180⁰

=> 90⁰+x = 180⁰

=> x= 180⁰-90⁰ =90⁰

Hence, that other angle is 90⁰

6. Angle Y is included between XY and YZ

7. Dot it yourself.

8. Refer to attachment

9. Side given = 4cm

Side given = 4cm Perimeter of equilateral triangle = 3× side = 3×4

Side given = 4cm Perimeter of equilateral triangle = 3× side = 3×4 =12cm

10. No we can't

Because of the fact that the sum of the three interior angles of a triangle must be 180 degrees, a triangle could not have two right angles.

11. Given Rational number = 2/5

We can write 2/5 as 2/5 × 5/5

= 10/25

12. 12/20 ,15/25, 18/30, 21/35

13. 36⁰and 144⁰

14. Refer to attachment

15. Refer to attachment

16. Refer to attachment

Answer 2

$\underline{ \underline{ \sf \red{ 1^{st} \:Answer }}} \red :$

$\rm \: ( - 1)x( - 2)x( - 3)x( - 4)x( - 1) {x}^{2}$

$= \rm \: - 24 \: {x}^{6}$

$\underline{ \underline{ \sf \red{ 2^{nd} \:Answer }}} \red :$

$\boxed{ \boxed{ \rm{Range = Highest \: value - Lowest \: value}}}$

$\implies \rm \: 70 - 5$

$= 65$

$\underline{ \underline{ \sf \red{ 3^{rd} \:Answer }}} \red :$

$\implies \rm x + 5 = ( - 12)$

$\rm x = - 12 - 5$

$\rm \: x = - 17$

$\underline{ \underline{ \sf \red{ 4^{th} \:Answer }}} \red :$

$\sf \: The \: triangle \: who \: side \: is \: not \: equal \: to \: any \: of \: its \: two \: sides$

$\sf \: in \: general : all \: sides \: of \: triangle \: measures \: differently \: to \: each \: other$

$\underline{ \underline{ \sf \red{ 5^{th} \:Answer }}} \red :$

$\rm \: Given$

$\rm \: Two \: angles \: of \: triangle \: are \: 48 ° \& \: 42°$

$\rm{Let \: third \: angle \: be \: x°}$

$\rm \: sum \: of \: angles \: in\: a \: triangle \: = 180°$

$\rm{48 + 42 + x = 180}$

$\rm{90 + x = 180}$

$\rm{x = 90°}$

$\underline{ \underline{ \sf \red{ 6^{th} \:Answer }}} \red :$

$\sf \angle \: y \: is \: beween \: XY \: and \: YZ$

$\underline{ \underline{ \sf \red{ 8^{th} \:Answer }}} \red :$

$\rm \: 3 {x}^{2} - 2x - 7 \: \: \: \: \: \: \: \: \\ \\ 3(2)^{2} - 2(2) - 7$

$= 3(4) - 4 - 7$

$= 12 - 11$

$= 1$

$\underline{ \underline{ \sf \red{ 9^{th} \:Answer }}} \red :$

$\boxed{ \boxed{ \sf \: Perimetre = Sum \: of \: all \: sides}}$

$\rm \implies perimetre \: = 4 + 4 + 4$

$= 12$

$\underline{ \underline{ \sf \red{ 10^{th} \:Answer }}} \red :$

No we cannot construct a triangle with two right angles (90°, 90°) because we know that sum of angles in a triangle is 180°. If there are two right angles then it directly sum up to 180°. So we cannot construct a triangle with two right angles.

$\underline{ \underline{ \sf \red{ 11^{th} \:Answer }}} \red :$

$\dfrac{2}{5} \times \dfrac{5}{5} = \dfrac{10}{25}$

$\underline{ \underline{ \sf \red{ 12^{th} \:Answer }}} \red :$

$\dfrac{3}{5} , \: \dfrac{6}{10} , \: \dfrac{9}{15} , \: \dfrac{12}{20}, \: \dfrac{15}{25} , \: \dfrac{18}{30} , \dfrac{21}{35}$

$\underline{ \underline{ \sf \red{ 13^{th} \:Answer }}} \red :$

Let the measure of the required angle be x°.

Then, the measure of its supplement is (x/4)°

Therefore, x + x/4 = 180

==> 4x + x= 720

==> 5x = 720

==> x = 144

$\underline{ \underline{ \sf \red{ 14^{th} \:Answer }}} \red :$

$\dfrac{5}{2} + \dfrac{2}{3}$

$= \dfrac{15 + 4}{6}$

$= \dfrac{19}{6}$

$\underline{ \underline{ \sf \red{ 15^{th} \:Answer }}} \red :$

$\rm \: 3n - 10 \: \: at \: \: n = 5$

$\implies \: 3(5) - 10$

$= 15 - 10$

$= 5$

$\underline{ \underline{ \sf \red{ 16^{th} \:Answer }}} \red :$

$\sf \: Area \: of \: parllelogram \: = 4 \: {cm}^{2}$

$\sf \: Base \: = \: 12 \: cm$

$\sf \: let \: Height \: be \: x \: cm$

$\sf \: We \: know \: that \: \: Area = base × height$

$\sf \: 12 \times x = 4$

$\sf \: x = \dfrac{4}{12}$

$\sf x = \dfrac{1}{3}$