Question

please answer the questions​

Answer 1

Answer:

6

Step-by-step explanation:

this is right answer math

Answer 2

Given:-

$\sf \dfrac{ \bigg ( x-2\sqrt{6} \bigg ) \bigg (5\sqrt{3} + 5\sqrt{2} \bigg )}{5\sqrt{3} - 5\sqrt{2}} = 1$

To find:-

The value of x.

Solution:-

$\sf \dfrac{ \bigg ( x-2\sqrt{6} \bigg ) \bigg (5\sqrt{3} + 5\sqrt{2} \bigg )}{5\sqrt{3} - 5\sqrt{2}} = 1$

$\sf \dashrightarrow \bigg ( x-2\sqrt{6} \bigg ) \bigg (5\sqrt{3} + 5\sqrt{2} \bigg )= 1\bigg (5\sqrt{3} - 5\sqrt{2}\bigg )$

$\sf \dashrightarrow x(5\sqrt{3}) + x(5\sqrt{2}) -2\sqrt{6}(5\sqrt{3}) -2\sqrt{6}(5\sqrt{2})= 5\sqrt{3} - 5\sqrt{2}$

$\sf \dashrightarrow 5\sqrt{3}x + 5\sqrt{2}x-30\sqrt{2} -20\sqrt{3}= 5\sqrt{3} - 5\sqrt{2}$

$\sf \dashrightarrow 5\bigg (\sqrt{3}x + \sqrt{2}x-6\sqrt{2} -4\sqrt{3}\bigg )= 5\bigg (\sqrt{3} - \sqrt{2} \bigg )$

$\sf \dashrightarrow \sqrt{3}x + \sqrt{2}x-6\sqrt{2} -4\sqrt{3}= \dfrac{\cancel{5}\bigg (\sqrt{3} - \sqrt{2} \bigg )}{\cancel{5}}$

$\sf \dashrightarrow \sqrt{3}x + \sqrt{2}x-6\sqrt{2} -4\sqrt{3}= \sqrt{3} - \sqrt{2}$

$\sf \dashrightarrow \sqrt{3}x + \sqrt{2}x= 6\sqrt{2}+4\sqrt{3}+\sqrt{3} - \sqrt{2}$

$\sf \dashrightarrow \sqrt{3}x + \sqrt{2}x= 6\sqrt{2} - \sqrt{2} +4\sqrt{3}+\sqrt{3}$

$\sf \dashrightarrow \sqrt{3}x + \sqrt{2}x= 5\sqrt{2} +5\sqrt{3}$

$\sf \dashrightarrow x \bigg (\sqrt{3}+ \sqrt{2}\bigg )= 5\bigg ( \sqrt{2} + \sqrt{3} \bigg )$

$\sf \dashrightarrow x =\dfrac{5\cancel{\bigg ( \sqrt{2} + \sqrt{3} \bigg )}}{\cancel{ \bigg (\sqrt{3}+ \sqrt{2}\bigg )} }$

$\bf\bullet \dashrightarrow \quad\boxed{\bf x =5}$

Hence, 5 is correct answer.