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Soln (a):
-4-3i
= 1/2( -8 - 6i)
= 1/2{ (3i)^ +(1)^ - 2.3i.1} ( Since, i^ = -1)
= 1/2{ ( 3i - 1)^}
Therefore,
Required square root of ( -4 - 3i)
= +- 1/√2( 3i - 1)
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