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1)
=√2/(2+√2)* (2-√2)/(2-√2)
=(2√2-2)/2
=2(√2-1)/2
=√2-1
given √2=1.414
=√2-1
=1.414-1=0.414
2)
=[1/(3-2√2)]∧2 + [1/(3+2√2)]∧2
=[1/(3-2√2) - 1/(3+2√2)] -2*1/(3-2√2)*1/3+2√2)
=[3+2√2+3-2√2]-2*
=6-2=4
3)
=√x + 1/√x
=(x+1)/√x
putting the value of x=7+4√3
=(7+4√3+1)/√(7+4√3)
=(8+4√3)/√(7+4√3)
i hope it is useful for you friend
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