please answer these for me
1. Draw a line AB and draw another line CD parallel to AB at a distance of 3.5 cm from it.
2. Construct a triangle LMN in which LM = 4.4 cm, MN= 6 cm and LN =5.3 cm.
3. Construct a triangle ABC in which AB=5 cm, AC= 6 cm and Z BAC = 50°. Measure the third side.
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Draw a line AB. 2. Take any two points P and Q on AB. 3. Construct ∠BPE = 90o and ∠BQF = 90o. 4. With P as center and radius equal to 3.5 cm, cut PE at R. 5. With Q as center and radius equal to 3.5 cm, cut QF at S. 6. Join CD and produce it on either side to get the required line CD parallel to AB and at a distance of 3 cm from it.Read more on Sarthaks.com - https://www.sarthaks.com/753007/draw-a-line-ab-and-draw-another-line-cd-parallel-to-ab-at-a-distance-of-3-5-cm-from-it
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