Math, asked by laurent23, 10 months ago

Please answer these questions.

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Answered by sandy1816

3

Step-by-step explanation:

(1)tanA-sinA/sin²A

=(sinA/cosA)-sinA/sin²A

=sinA-sinAcosA/sin²AcosA

=sinA(1-cosA)/(1-cos²A)cosA

=sinA/(1+cosA)cosA

=sinA/cosA.1/(1+cosA)

=tanA/(1+cosA)

(2)tan²A-sin²A

=sin²A-sin²Acos²A/cos²A

=sin²A(1-cos²A)/cos²A

=tan²Asin²A

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