Question

please answer these questions​

Answer 1

Q.5) Given :

⬤ Area of Trapezium is 34 cm².

⬤ Length of one of its Parallel Side is 10 cm.

⬤ Height of Trapezium is 4 cm.

To Find :

⬤ Length of the Other Parallel Side of Trapezium .

Formula Used :

$\bf[\:{Area\:of\: Trapezium=\dfrac{1}{2}\times{(Sum\:of\:Parallel\:Sides)}\times{h}\:]}$

• h = height

Solution :

Let :

• Length of Other Parallel Side of Trapezium be x .

According to the Formula :-

34 = 1/2 × (Sum of Parallel Sides) × h

34 = 1/2 × (10 + x) × 4

(34 × 2) = 40 + 4x

68 = 40 + 4x

60 - 40 = 4x

28 = 4x

28/4 = x

7 = x

Therefore , The Length of Other Parallel Side of Trapezium is 7 cm.

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Q.6) Given :

⬤ 4p²q - 3pq + 5pq² - 8p + 7q - 10 from 18 - 3p - 11p + 5pq - 2pq².

Solution :

18 - 3p - 11p + 5pq - 2pq² - (4p²q - 3pq + 5pq² - 8p + 7q - 10)

18 - 3p - 11q + 5pq - 2pq² + 5p²q - 4p²q + 3pq - 5pq² + 8p - 7q + 10

Combining Like Terms :-

(18 + 10) + (-3p + 8p) + (-11q - 7q) + (5pq + 3pq) + (-2pq² - 5pq²) + (5p²q - 4p²q)

28 + (5p) + (-18q) + (8pq) + (-7pq²) + (p²q)

28 + 5p - 18q + 8pq - 7pq² + p²q

Therefore , Answer is 28 + 5p - 18q + 8pq - 7pq² + p²q .

Answer 2

Step-by-step explanation:

$(18 - 3p - 11q + 5pq - 2p {q}^{2} + 5 {p}^{2} q) - (4 {p}^{2} q - 3pq + 5p {q}^{2} - 8p + 7q - 10)$

$= 18 - 3p - 11q + 5pq - 2p {q}^{2} + 5 {p}^{2} q - 4 {p}^{2} q + 3pq - 5 p {q}^{2} + 8p - 7q + 10$

$= 5p - 18q + 8pq - 7p {q}^{2} + {p}^{2} q + 28$