Biology, asked by ƒaiŗƴ, 6 months ago

please Answer these Questions step by step...... ​

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Answered by guptasant72
1

Answer:

An ECG records the electrical signal from your heart to check for different heart conditions.

Electrodes are placed on your chest to record your heart's electrical signals, which cause your heart to beat.

The signals are shown as waves on an attached computer monitor or printer.

Answered by nehu215
1

Solution:-

2) The projection length of the vector 3i + 1j + 2k on y-z Plane is

\to \rm\: vector \: = 3i \: + 1j \: + 2k \:→vector=3i+1j+2k

we know that

=> y is called j and k is called z

To find projection length of Y - Z , use this formula

\begin{gathered}\rm \: length \: = \sqrt{ {y}^{2} + {z}^{2} } = \sqrt{1 {}^{2} + {2}^{2} } \\ = \sqrt{1 + 4} = \sqrt{5}\end{gathered}

length= y 2 +z 2

= 1 2 +2 2= 1+4 = 5

Answer

\rm \: = \sqrt{5}=

5

2) The projection length of the vector 3i + 1j + 2k on X - Z Plane is

\to \rm\: vector \: = 3i \: + 1j \: + 2k \:→vector=3i+1j+2k

=> x is called i and k is called z

\begin{gathered}\rm \: length \: = \sqrt{ {x}^{2} + {z}^{2} } = \sqrt{3 {}^{2} + {2}^{2} } \\ = \sqrt{9 + 4} = \sqrt{13}\end{gathered}

length= x 2 +z 2

= 3 +2 2

= 9+4 = 13

Answer

= \sqrt{13}=

13

4) if A = 2i - 3j + 4k, its components along xy plane is

\rm \:vector \to \: 2i - 3j + 4kvector→2i−3j+4k

Component along xy plane is

\begin{gathered}\rm \: components \: along \: xy \: plane \: is \\ = \rm \sqrt{ {x}^{2} + {y}^{2} } = \sqrt{ {2}^{2} + ( - 3) {}^{2} } = \sqrt{4 + 9} = \sqrt{13}\end{gathered}

components along xy plane is

= x 2+y 2

= 2 2 +(−3) 2

= 4+9 = 13

5. if A = 2i - 3j + 4k, its components along yz plane is

\rm \:vector \to \: 2i - 3j + 4kvector→2i−3j+4k

Component along yz plane is

\begin{gathered}\rm \: components \: along \: yz \: plane \: is \\ = \rm \sqrt{ {y}^{2} + {z}^{2} } = \sqrt{ {( - 3)}^{2} + ( 4) {}^{2} } = \sqrt{9 + 16} = \sqrt{25} = 5\end{gathered}

components along yz plane is

= y 2 +z 2

= (−3) 2 +(4) 2

= 9+16 = 25 =5

6.if A = 2i - 3j + 4k, its components along xz plane is

\rm \:vector \to \: 2i - 3j + 4kvector→2i−3j+4k

Component along xz plane is

\begin{gathered}\rm \: components \: along \: xz \: plane \: is \\ = \rm \sqrt{ {x}^{2} + {z}^{2} } = \sqrt{ {( 2)}^{2} + ( 4) {}^{2} } = \sqrt{4+ 16} = \sqrt{20} = 2 \sqrt{5}\end{gathered}

componentsalong xz plane is

= x 2 +z 2

= (2) 2 +(4) 2

= 4+16

= 20 =2 5

7. The projection length of the vector 2i - 4j - 6k on xy Plane is

\rm \to \: vector = 2i - 4j - 6k→vector=2i−4j−6k

The projection length of xy is

\begin{gathered}\rm \: \sqrt{ {x}^{2} + {y}^{2} } = \sqrt{ {2}^{2} + (- 4) {}^{2} } \\ = \sqrt{4 + 16} = \sqrt{20} = 2 \sqrt{5}\end{gathered} x 2 +y 2

= 2 2 +(−4) 2

= 4+16 = 20 =2 5

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