Question

Q46) The density (in g/L) of CH4 gas present in 1 litrevessel at 2 atm and 400 K is [R = 0.8 atm-L/mol K]​

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Answer 1

Answer:

0.75g/l

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Answer 2

Answer:

The density (in g/L) of CH4 gas present in 1 litrevessel at 2 atm and 400 K is 0.975 kg / $m^{3}$  or 975 g/cc

Step-by-step explanation:

From the above question,

They have given :

The density (in g/L) of CH4 gas present in 1 litrevessel at 2 atm and 400 K is [R = 0.8 atm-L/mol K]​

                  n = PV/RT

Substituting the given values, we get:

                   n = (2 atm x 1 L) / (0.8 atm-L/mol K x four hundred K)

                   n = 1.25 mol

The mass of CH4 gasoline can be calculated the usage of its molar mass, which is 16.04 g/mol. So, the mass of 1.25 moles of CH4 gasoline is:

                    m = 1.25 mol x 16.04 g/mol

                    m = 20.05 g

The density of CH4 gasoline is the mass of the gasoline divided via its volume:

                PM = d X RT

                    d = $\frac{PM}{RT}$

                    d = $\frac{2 X 16}{\frac{22.4}{273} X 400 }$

                    d = 0.975 kg / $m^{3}$  or 975 g/cc            

Hence,

        The density (in g/L) of CH4 gas present in 1 litrevessel at 2 atm and 400 K is 0.975 kg / $m^{3}$  or 975 g/cc

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